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static List<int> Lotto() => Enumerable.Range(1, 49).OrderBy(x => Guid.NewGuid()).Take(6).OrderBy(x => x).ToList();
var lst = Enumerable.Range(0, 3).Select(x => Lotto()).ToList();
lst.ForEach(x => Console.WriteLine(string.Join(", ", x)));
                

Lösung von: Jens Kelm (@JKooP)

function lotteryNumbers(min = 1, max = 49, num = 6) {
  let out = [];
  while (out.length < num) {
    let cur = Math.floor(Math.random() * (max - min + 1) + min);
    if (out.indexOf(cur) == -1) out.push(cur);
  }
  return out.sort(function(a, b) {return a - b});
}

let list = [], i;
for (i = 1; i <= 3; i++) list.push(lotteryNumbers());
console.log(list);

                

Lösung von: Lisa Salander (Heidi-Klum-Gymnasium Bottrop)

// Achtung: F#
let lotto a b = [a .. b] |> List.sortBy (fun _ -> System.Random().Next()) |> List.take(6) |> List.sort

let ziehung n = 
    let mutable lst = []
    for _ in 1 .. n do 
        lst <- [lotto 1 49] |> List.append lst
    lst

printfn "%A" (ziehung 3)
                

Lösung von: Jens Kelm (@JKooP)

#include <iostream>
#include <vector>
#include <algorithm>

std::vector<int> lottery_numbers() {
    std::vector<int> v;
    auto c{ 0 };
    while (c < 6) {
        auto r{ rand() % 49 + 1 };
        if (std::find(v.begin(), v.end(), r) == v.end()) {
            v.push_back(r);
            c++;
        }
    }
    std::sort(v.begin(), v.end());
    return v;
}

std::vector<std::vector<int>> list_lottery_numbers(int n) {
    std::vector<std::vector<int>> v;
    for (size_t i = 0; i < n; i++)
        v.push_back(lottery_numbers());
    return v;
}

void print_lottery_numbers(const std::vector<std::vector<int>>& v) {
    for (const auto& l : v) {
        for (const auto& n : l)
            std::cout << n << " ";
        std::cout << std::endl;
    }
}

int main() {
    srand(time(NULL));
    print_lottery_numbers(list_lottery_numbers(3));
}
                

Lösung von: Jens Kelm (@JKooP)

import random
def lotto_numbers():
    return sorted(random.sample(range(1, 50), k=6))
print([lotto_numbers() for _ in range(3)])
                

Lösung von: Name nicht veröffentlicht

Lottery Omelette.

Your Chef-recipe to 6 from 49 wealth and prosperity. No liability assumed. 
<lissalanda@gmx.at>

Ingredients.
3 Fabergé eggs

Method.
Whisk Fabergé eggs. Serve with random sauce. Whisk Fabergé eggs until whisked.


Random Sauce.

Ingredients.
49 diamonds
6 pennies

Method.
Grind diamonds. Put diamonds into mixing bowl. Grind diamonds until 
grinded. Mix the mixing bowl well. Flip pennies. Fold diamonds into mixing
bowl. Put diamonds into 2nd mixing bowl. Flip pennies until flipped. Pour
contents of the 2nd mixing bowl into the baking dish. Clean mixing bowl.
Refrigerate.
                

Lösung von: Lisa Salander (Heidi-Klum-Gymnasium Bottrop)